Wednesday, January 20, 2010

New Balance Wt Why The Pan Of A Traditional Balance Stops Going Farther Down When We Put A Small Wt. On It, What Force Stops?

Why the pan of a traditional balance stops going farther down when we put a small wt. on it, what force stops? - new balance wt

In other words, a pan with a little weight weighs more than another empty plates, bus stops, get off the force.
A little more weight you go down and start from scratch, why?

3 comments:

prags said...

Focus of the two pots, and the balance of the weapons is just below the focal point, if inclined, the center of gravity, attempts to balance the weight so inclined stop bit.

shimrod said...

This behavior is at the center of mass of the moving part of the normal range (the horizontal bar are among those which the two plates) under the focal point of the system or the point that resists the movement outside the "horizontally, like a pendulum . The center of mass could be reduced, for example, if both arms are slightly bent away from the city center - but it was not so obvious. It was probably designed so dass

If R is the distance between the center of mass below the pivot point, M the mass of this structure, L is the length of one arm and m is the mass balance weight on the scales, travel around in a corner (with the horizontal):

theta = asin (Lm / RM)

For relatively small masses m, m. theta roughly proportional to If R is zero theta -> 90

The Grand Inquisitor said...

As part of the object, in turn, the weight vector of the pivot raises the arm. This "time" is calculated by the force times distance. As the distance increases, increases the time that corresponds to the time of the fixed-weight resistance. In other words, you have 2 variables, weight and distance. Once you fit the weight of the other variables must change in order to balance the equation. Thus, the distance to the arm in the pan with the pivot credit will be reduced to zero Equillibrium reach.

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